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Log in[Chia sẻ] Form giải phương trình bậc 2 cho forum toán học
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[Chia sẻ] Form giải phương trình bậc 2 cho forum toán học
by adkhamphait Fri Feb 10, 2012 9:38 am
Giải nhanh chóng phương trình bậc 2 dạng Ax2 + Bx + C = 0. Khi vô nghiệm, kết quả sẽ báo "Sai".
code:
- Code:
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<div class='main section' id='main'><div class='widget Blog' id='Blog1'>
<SCRIPT type="text/javascript">
<!-- Begin
function quad(form) {
a=eval(form.a.value);
b=eval(form.b.value);
c=eval(form.c.value);
x1=-b/2/a+Math.pow(Math.pow(b,2)-4*a*c,0.5)/2/a;
x2=-b/2/a-Math.pow(Math.pow(b,2)-4*a*c,0.5)/2/a;
form.x1.value = x1;
form.x2.value = x2;
if (form.x1.value == "NaN") form.x1.value="Sai!";
if (form.x2.value == "NaN") form.x2.value="Sai!";
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<center>
<form name=form>
<table border=1 cellpadding=2>
<tr>
<td colspan=2 align=center><b>Giải phương trình bậc 2:<br>Ax<sup>2</sup> + Bx + C = 0</b></td>
</tr>
<tr>
<td>
<center><table border=1 width=100% cellpadding=2>
<tr>
<td align=center><b>A = </b></td>
<td align=center><input type=text size=6 name="a"></td>
</tr>
<tr>
<td align=center><b>B = </b></td>
<td align=center><input type=text size=6 name="b"></td>
</tr>
<tr>
<td align=center><b>C = </b></td>
<td align=center><input type=text size=6 name="c"></td>
</tr>
</table>
</td>
<td>
<center><table border=1 width=100% cellpadding=2>
<tr>
<td colspan=2 align=center><input type=button value="Nghiệm" onClick="quad(this.form)"></td>
</tr>
<tr>
<td align=center><b>X1 = </b></td>
<td align=center><input type=text size=6 name="x1"></td>
</tr>
<tr>
<td align=center><b>X2 = </b></td>
<td align=center><input type=text size=6 name="x2"></td>
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</td>
</tr>
</table>
</form> </center></center></center>
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adkhamphait- Giới tính :
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